# Caver-js invalid fee payer 질문

**URL:** https://devforum.kaia.io/t/caver-js-invalid-fee-payer/250
**Category:** Caver
**Tags:** caver-js
**Created:** [7월 1, 2020, 6:16오전 UTC](https://devforum.kaia.io/t/caver-js-invalid-fee-payer/250 "2020-07-01T06:16:16Z")
**Posts on this page:** 3
**Page:** 2

<div class="post-metadata">

### Author: ![G\_Kurk](https://yyz1.discourse-cdn.com/flex035/user_avatar/devforum.kaia.io/g_kurk/32/184_2.png) [@G\_Kurk](https://devforum.kaia.io/u/G_Kurk)
#### Post date: [7월 1, 2020, 12:26오후 UTC](https://devforum.kaia.io/t/caver-js-invalid-fee-payer/250/22 "2020-07-01T12:26:53Z")

</div>

크 완전 감사합니다.

```auto
RoleBasedKeyring {
  _address: '0xfd19936562747321d37e0df555aa03fd075c3145',
  _keys: [[ [PrivateKey] ], [[PrivateKey] ], [[PrivateKey] ] ] }

```

이렇게 잘 나옵니다.

늦은 시간에도 감사해요!

---

<div class="post-metadata">

### Author: ![G\_Kurk](https://yyz1.discourse-cdn.com/flex035/user_avatar/devforum.kaia.io/g_kurk/32/184_2.png) [@G\_Kurk](https://devforum.kaia.io/u/G_Kurk)
#### Post date: [7월 1, 2020, 12:27오후 UTC](https://devforum.kaia.io/t/caver-js-invalid-fee-payer/250/23 "2020-07-01T12:27:30Z")

</div>

Fee delegation signing 해보고 말씀드릴게요!

---

<div class="post-metadata">

### Author: ![G\_Kurk](https://yyz1.discourse-cdn.com/flex035/user_avatar/devforum.kaia.io/g_kurk/32/184_2.png) [@G\_Kurk](https://devforum.kaia.io/u/G_Kurk)
#### Post date: [7월 1, 2020, 1:14오후 UTC](https://devforum.kaia.io/t/caver-js-invalid-fee-payer/250/24 "2020-07-01T13:14:52Z")

</div>

테스트 환경  
Network : Baobab.  
SDK : Caver-js v 1.5.0 ( Fee delegation tx 사용시 )  
Caver-js v 1.4.1 ( Account update 사용시 )  
Ken version : 1.3.0

테스트 시나리오

1. ken attach
2. personal.newAccount 로 Acc 생성
3. Caver-js v 1.4.1 로 Account update 실행
4. caver.klay.accounts.encrypt 실행이후 나오는 Result 를 for 문으로 추출
5. Result 를 json 파일로 변환
6. Caver-js v 1.5.0 Fee delegation tx 테스트 ( TxtypeFeeDelegatedValuetransfer 테스트 )
7. 사이닝 완료 및 TxHash 를 Baobab 네트워크에서 확인

잘 됩니당.

참고차 남겨드립니다. 🙂

[이전 페이지](https://devforum.kaia.io/t/caver-js-invalid-fee-payer/250.md?page=1)
